by tim Sat Mar 26, 2016 9:14 pm
First, you don't actually need to calculate x to answer a DS problem. However, I'm not sure you could convince yourself that the statements together are sufficient without pretty much solving for x anyway, so let's take it from there.
Consider quadrilateral PQSU:
90 + PQS + x + SUP = 360
From the two triangles you've identified as isosceles:
RSQ = RQS = 180 - PQS
TSU = SUT = 180 - SUP
Now use this fact:
RSQ + x + TSU = 180
and sub in the information from the previous pair of equations:
180 - PQS + x + 180 - SUP = 180
Add this to the top equation:
90 + PQS + x + SUP + 180 - PQS + x + 180 - SUP = 360 + 180
2x + 450 = 540
2x = 90
x = 45
I'm not saying this is the fastest way to do it, but it works. If you're just looking for a fast way to realize x is calculable without calculating it, consider that x plus two angles is 180, and x plus the supplements of those two angles is 270. From here you may be able to see that you can solve for x, but if you don't, you HAVE to do something more concrete like what I did above.
Tim Sanders
Manhattan GMAT Instructor
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