hakobc Wrote:rmyoungsc Wrote:Ok I misunderstood the law. It only applies to the lengths of the sides of a triangle, not the degree measure of the angles in a triangle. thanks
I agree with you, but I think if the lengths of the sides of triangle are equal, that means their conrresponding angles are also equal to each other, thus I also don't agree with the original answer choice.
I am stuck on this and I think if 40 gonna be any angle in the isosceles triangle, then you can easily find the rest of angles! please comment if you not agree!
incorrect on 2 counts.
first of all,
WE DON'T KNOW WHICH TWO ANGLES ARE EQUAL. there are two possibilities for an isosceles triangle with a 40° angle in it:
(case 1) 40°, 40°, 100° (if angle S = 40° is one of the two equal angles)
(case 2) 40°, 70°, 70° (if angle S = 40° is NOT one of the two equal angles)
worse yet -
it would still be insufficient even if only case (1) were possible!this is because there are two DIFFERENT angles - 100° and the other 40° - remaining, and
you don't know which of these is angle T. i.e., angle T could still be either 40° or 100° in this case.
so you don't even need to come up with case 2 in order to prove insufficient!