I am having trouble with the math used in the explanation. Please read:
If x is an integer, is 2^x less than 80?
(1) 4^x-1 < 4^x - 120
(2) x^2 = 36
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Since 26 = 64 and 27 = 128, 2x will be less than 80 only if the integer x is less than 7. So, we can rephrase the question as follows: "Is x < 7?"
The answer is (B), but, but when you read the explanation I have trouble following the math for statement one.
(1) INSUFFICIENT: We can solve the inequality for x.
4^x-1 < 4^x - 120
4^x-1 - 4^x < -120
4^x(4^-1) - 4^x < -120
4^x(1/4) - 4^x < -120
4^x[(1/4) - 1] < -120
4^x(-3/4) < -120
4^x > 160
How do you go from
4^x(1/4) - 4^x < -120
to
4^x[(1/4) - 1] < -120
Where does the 1 come from?
Since 43 = 64 and 44 = 256, x must be greater than 3. However, this is not enough to determine whether x < 7.
(2) SUFFICIENT: If x^2 = 36, then x = 6 or -6. Either way, this is enough to determine whether x < 7.
The correct answer is B.