tim Wrote:However, on further reflection, I notice that your calculation actually wasn't as unhelpful as we both thought. Observe:
Process#2
mx + ky > kx + my ??
mx - kx + ky - my > 0 ??
x(m - k) + y(k -m) > 0 ??
x(m - k) - y(m - k) > 0 ??
(x - y)(m - k) > 0 ??
Notice how you had an (m-k) factor as well as a (k-m) factor. When you see this, you should factor out a -1 from one of these terms (it doesn't matter which one) so that you have two like terms and can factor further.
Yes ... this is what I was looking for :) Thank you so much Tim