If a < 0, then sqr rt -a * [a] is ?
while this problem originally had variable x, I changed it to a to minimize confusion.
[a] = absolute value of a.
Question reads under radical sign: -a times absolute value of a. With a < 0.
Answers
-a
-1
1
a
sqr rt a.
I thought that if a was less than 0, then clearly a must be negative. So -a= negative times negative which equals positive a times absolute value of a which by rule has to be positive. So positive times positive = a^2 and under radical sign, a^2 = a. For that reason I chose answer a for the answer and was shocked to learn that -a (being -x was actually the answer). What am I doing wrong here? Thanks in advance.