If -2x > 3y, is x negative?
1) y > 0
2) 2x+5y-20=0
The correct answer is D (both sufficient).
------------------
Statement 1 is easy, x would have to be negative in order for -2x to be a positive number greater than 3y (since y is positive).
Statement 2: This is where I'm stuck. Can you just do this?
-2x = GT(3y) (from first equation, GT = greater than)
2x = LT(-3y) (divide both sides by -1 and flip the inequality)
2x+5y-20=0 (substitute LT(-3y) for 2x)
LT(-3y)+5y-20=0
LT(2y)=20
LT(y)=10
y> 10 (since y must be greater than 10, it must be positive, therefore sufficient?)
mdh