If -2x > 3y, is x negative

[kourakis]

(1) y>0
(2) 2x+5y-20=0

OA is D

Nice problem. Initially I thought it is A, but after the following reasoning I chose D. Is there any better way of solving this?

solution:

(1) -2x>3y. If y>0, then x needs to be negative (zero would not work). Sufficient

(2) break down equation as follows

2x+5y-20=0 >>
(2x+3y)+2y-20=0>>
At this point we note that 2x+3y is negative (given statement), and that -20 is negative. Therefore 5y HAS to be positive. Since -2x>3y, x is negative. Sufficient

[RonPurewal]

here is one solution
post11370.html#p11370

if you have further questions, please post them on that thread. thanks.