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If (1/5)^m (1/4)^18=1/2(10)^35, then m=?

by spinmove Sun Jun 08, 2008 11:04 pm

If (1/5)^m (1/4)^18=1/2(10)^35, then m=?

1) 17
2) 18
3) 34
4) 35
5) 36

Answer is 35. I tried setting bases equal to each other, but the (1/5)^m threw me off. Any suggestions? Thank you.
RonPurewal
Students
 
Posts: 19744
Joined: Tue Aug 14, 2007 8:23 am
 

Re: If (1/5)^m (1/4)^18=1/2(10)^35, then m=?

by RonPurewal Mon Jun 09, 2008 2:53 am

spinmove Wrote:If (1/5)^m (1/4)^18=1/2(10)^35, then m=?

1) 17
2) 18
3) 34
4) 35
5) 36

Answer is 35. I tried setting bases equal to each other, but the (1/5)^m threw me off. Any suggestions? Thank you.


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