A Triangle ABC is given with 2 angles : x,y are angles lying across AC and AB ,respectively.
Is triangle ABC isosceles?
1/ X does not equal Y
2/ AB=2BC
The answer given by MGMAT is (C) - both assumptions are needed.
( 1-If x and Y are different it tells us nothing about the third angle AND2- if AB=2BC, BC could still equal AC the )
I think there's a mistake in the answer and the answer is really (B)- meaning that the second piece of information suffices. If AB=2BC and BC+AC must be >AB (triangle rules) , than AC+BC>2BC and AC>BC. i.e. they are not equal and the triangle ABC cannot an isoceles if all sides are different!
Have I reached the wrong conclusion?