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pseizert
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Adding Powers

by pseizert Wed Feb 15, 2012 8:18 am

Had this question in a practice exam. Seemed too easy when I took it; turns out my feelings were correct and I got the answer wrong. Any insights?

2 + 2 + 2^2 + 2^3 + 2^4 + 2^5 + 2^6 + 2^7 + 2^8 =

a:2^9
b:2^10
c:2^16
d:2^35
e:2^37
stud.jatt
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Re: Adding Powers

by stud.jatt Wed Feb 15, 2012 10:26 pm

the key in solving this quickly lies in realizing that

2^x + 2^x = 2*2^x = 2^(x+1)

start with the first two terms

2 + 2 = 2^2

then add the next one to this

2^2 + 2^2 = 2^3

repeating the same step

2^3 +2^3 = 2^4 and so one...

you don't have to calculate all the way to 2^8, just a cursory look at this pattern will tell you that the last two terms we will have are

2^8 + 2^8 = 2^9 which is the answer



pseizert Wrote:Had this question in a practice exam. Seemed too easy when I took it; turns out my feelings were correct and I got the answer wrong. Any insights?

2 + 2 + 2^2 + 2^3 + 2^4 + 2^5 + 2^6 + 2^7 + 2^8 =

a:2^9
b:2^10
c:2^16
d:2^35
e:2^37
RonPurewal
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Posts: 19744
Joined: Tue Aug 14, 2007 8:23 am
 

Re: Adding Powers

by RonPurewal Fri Feb 17, 2012 5:58 am

read here:
post25467.html#p25467

this thread is now locked. PLEASE search the forum for existing threads before you post -- we don't want to create a million zillion threads about the same problem. thanks.