The student wrote:
My naif way to figure x out from st.1 would be:
3w+2=56--->w=18
I'm aware, though, that I'm not taking in account the combinations/permutations situation + the other group involved in the permutation/combination. Indeed, I'm missing how to integrate and translate those info in the equation above.
Before you consider any of the mathematics below, remember that
there's no need to calculate anything for this statement.If you were actually required to calculate something, the problem would almost certainly be less laborious than this one.
So"”just to be redundant"”
it is extremely unlikely that you'll ever have to do anything like the below. But, for the sake of completeness, here it is anyway.
* 56 is a small number, so, if I had to calculate this, I wouldn't bother with algebra. I'd just try modest-sized numbers and see what happens.
If there are six women, the number of combinations is (6*5*4)/3! = 20. Too small.
If there are seven women, the number of combinations is (7*6*5)/3! = 35. Still too small.
If there are eight women, the number of combinations is (8*7*6)/3! = 56. Boom. So you have 8 - 2 = 6 women.