A certain panel is to be composed of exactly three women...

[pujaverma]

A certain panel is to be composed of exactly three women and exactly two men, chosen from x women and y men. How many different panels can be formed with these constraints?

This is a data sufficiency question, and I understand that with certain information, this problem can be solved. If you did have to solve for a value, I am unsure how to solve it.

For example, if x=6 and y=5 (like in the problem itself), I assume you would then do the combination formula of 6C3 and 5C2, to see how many subgroups of women and men can be made. What would be the next step?

[sunny.jain]

exactly 3 women and exactly 2 men
out of
6 women and 5 men

===> 6C3 and 5C2

==> 6C3*5C2 --> Answer.

[pujaverma]

thank you for your help!

[esledge]

Exactly right! The DS take-away: you need to knowing what you would do with the values and/or variables on PS, so that you can identify the missing info. On this one, the missing info was "What is x and what is y?"

[VaibhavA772]

I know this is a DS problem but I just want to make sure the actual answer if it were to be given would be 200 (20*10) total panels. Is that correct?

[Sage Pearce-Higgins]

I believe that 200 is correct if we're counting the number of different panels choosing 3 out of 6 women and 2 out of 5 men.

Take a look at this post here: https://www.manhattanprep.com/gmat/foru ... tml#p95673