Errata – GMAT Advanced Quant, 2nd Edition
Cover for 2nd Edition
Release Date:
May 19, 2015
2.0
| Page | Loc | Description | Erroneous Text | Correction |
|---|---|---|---|---|
| 31 |
Chapter 0 Solution to Try-It #0-3 |
Answer choice (A) should be 3.8. | (A) 4.8 | (A) 3.8 |
| 42 |
Chapter 1 Try-It #1-4 |
The second example of the “square of an odd integer” should be 32. | 33 | 32 |
| 47 |
Chapter 1 Problem Set |
In problem #2, the second x in the question stem should be an exponent. It should read (24)5+2x(36)6(17)3. | (24)5+2x(36)6(17)3 | (24)5+2x(36)6(17)3 |
| 62 |
Chapter 2 Try-It #2-3 |
The correct answer is choice E, not D. Under the paragraph “What characteristic must be true…”, the second letter choice is mistakenly listed as E. | E | D |
| 64 |
Chapter 2 Try-It #2-4 |
The integers listed in the first sentence of the explanation of case 3 are incorrect. | Case 3: If n = 3, then the three consecutive integers are 3, 4, and 5. | Case 3: If n = 3, then the three consecutive integers are 2, 3, and 4. |
| 135 |
Chapter 4 Problem Set |
Problem #5, statement (2) should read 2x < x2. | 2x < x2 | 2x < x2 |
| 142 |
Chapter 4 Problem Set Solutions |
Statement 2 of problem 9 is incorrectly stated as “SUFFICIENT”. It should be “INSUFFICIENT” as the answer to the problem is E. | (2) SUFFICIENT | (2) INSUFFICIENT |
| 150 |
Chapter 5 Try-It #5-1 |
The general formula for the cumulative sum should have 2 raised to the n power in the numerator | ||
| 158 |
Chapter 5 Try-It #5-8 |
The statement should also specify z will be positive. | x = 1010 – z, where z is a two-digit integer. | x = 1010 – z, where z is a positive two-digit integer. |
| 166 |
Chapter 5 Problem Set Solutions |
In the solution for question 8, the final sentence in the first paragraph starting with “When 5 is…” has been replaced. See corrections column. | When 5 is raised to an odd power, the remainder is 1, but when 5 is raised to an even power, the remainder is 2. | When 5 is raised to an odd power, the remainder is 2, but when 5 is raised to an even power, the remainder is 1 |
| 176 |
Chapter 6 Try-It #6-3 |
Try-It Problem #6-3 is flawed because the two statements contradict each other. This is not allowed on the GMAT. A new version will be written for re-print. |
(1) n is prime (2) n < 3 |
|
| 181 |
Chapter 6 Problem Set |
Problem #7, the n should be a part of the exponent on both sides. | (-3)4n = (3)7n-3 | (-3)4n = (3)7n-3 |
| 221 |
Chapter 7 Problem Set Solutions |
In problem 10, the answer is incorrect. It should be (A): None. | (C) II only: | (A): None. |
| 222 |
Chapter 7 Problem Set Solutions |
In the solution to question 10 under Statement II, the final sentence (“Statement II is never true…”) has been replaced. See the “Correction” column. | Statement II is never true, so eliminate answers (A) and (D). | However, the standard deviation could be between 0 and 1. If so, then the square of the standard deviation (aka, the variance) would actually be less than the standard deviation. For instance, if you had 1,000 instances of the number 60 and one instance of the number 30, then the standard deviation would be about 0.95 and the variance would be about 0.9. (You do not, of course, need to calculate this! It’s enough to know that an extreme case is a possibility.) |
| 222 |
Chapter 7 Problem Set Solutions |
The solution to question 10 is incorrect. | The correct answer is (C). | The correct answer is (A). |
| 232 |
Chapter 8 Try-It #8-4 |
Solution to Try-It #8-4. In the explanation, the three instances of the variable n should be exponents (not multiplication). It should be two instances of (1/3)n and 3n > 100. | (1/3)n and 3n > 100 | (1/3)n, and 3n > 100 |
| 242 |
Chapter 8 Problem Set Solutions |
For question 9’s solution, the explanation for statement 2’s reference to “third largest” should be changed to “second largest”. | third largest | second largest |
| 242 |
Chapter 8 Problem Set Solutions |
In question 10’s solution, the second example in statement (2)’s explanation should read: “It’s also possible that z = 9, y = 6, and x = 4.” | It’s also possible that z = 9, y = 36, and x = 4. | It’s also possible that z = 9, y = 6, and x = 4. |
| 275 |
Chapter 9 Workout Set 3 Solutions |
Solution to #25, 3rd paragraph should read “The only possible units digits for perfect squares are 0, 1, 4, 5, 6, and 9.” | The only possible units digits for perfect squares are 0, 1, 2, 5, 6, and 9. | The only possible units digits for perfect squares are 0, 1, 4, 5, 6, and 9. |
| 275 |
Chapter 9 Workout Set 3 Solutions |
Solution to #25, answer choice D should read “3,363, so y + 1 = 3,364. Units digit okay.” | 3,363, so y + 1 = 3367. Units digit okay | 3,363, so y + 1 = 3,364. Units digit okay. |
| 298 |
Chapter 9 Workout Set 6 |
Problem #59. The question stem is missing the word, “consecutive.” | Set M contains seven integers… | Set M contains seven consecutive integers… |