“Here are the free GMAT events we’re holding this week. All times are local unless otherwise specified.

11/17/13– Online – Free Trial Class-  7:00AM- 10:00AM (EDT)

11/17/13- Santa Monica, CA- Free Trial Class- 5:30PM- 8:30PM

11/18/13-Boston, MA- Free Trial Class- 6:30PM- 9:30PM

11/18/13–  Austin, TX- Free Trial Class- 6:30PM- 9:30PM

11/19/13– Toronto, ON- Free Trial Class - 6:30PM- 9:30PM

11/19/13– Online- MBA Admissions Myths Destroyed presented by mbaMission- 5:00PM- 6:30PM (EDT)

11/19/13– Online - Free Trial Class-  8:00PM- 11:00PM (EDT)

11/20/13– New York, NY- Essay Writing Workshop presented by mbaMission-  7:00PM- 8:30PM

11/21/13– Online- Thursdays with Ron- 7:00PM- 8:30PM (EST)

11/21/13– Boston, MA- Choosing the Right B-School presented by mbaMission- 7:00PM-8:30PM

11/23/13– New York, NY - Free Trial Class- 2:00PM-5:00PM

Looking for more free events? Check out our Free Events Listings Page.”

“

We invite you to test your GMAT knowledge for a chance to win! Each week, we will post a new Challenge Problem for you to attempt. If you submit the correct answer, you will be entered into that week’s drawing for a free Manhattan GMAT Prep item. Tell your friends to get out their scrap paper and start solving!

Here is this week’s problem:

In the diagram above, triangle ABC is equilateral, figure SQRE is a square, and A is the midpoint of SQ. If the perimeter of triangle ABC is 6 inches, what is the length, in inches, of segment RY ?

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“Here are the free GMAT events we’re holding this week. All times are local unless otherwise specified.

11/11/13– Durham, NC – Free Trial Class-  6:30PM- 9:30PM

11/11/13- Online- Free Trial Class- 8:00PM- 11:00PM (EDT)

11/11/13-Online- Live Online GMAT Preview- 9:00PM- 10:30PM

11/11/13–  London- Free Trial Class- 6:30PM- 9:30PM

11/11/13– Ann Arbor, MI- Open House- Earn $100/hr Teaching with Manhattan Prep - 5:30PM- 6:30PM

11/12/13– San Diego, CA- Free Trial Class- 6:30PM- 9:30PM

11/12/13– Santa Monica, CA - Free Trial Class-  6:30PM- 9:30PM

11/13/13– Arlington, VA- Free Trial Class -  6:30PM- 9:30PM

11/13/13– Glendale, CA  -Free Trial Class – 7:00PM- 8:30PM

11/13/13– San Francisco, CA- Free Trial Class- 6:30PM-9:30PM

11/14/13– New York, NY - Free Trial Class- 6:30PM-9:30PM

11/14/13– Online - Free Trial Class-  9:00PM- 12:00AM

11/14/13– Chicago, IL - Free Trial Class-  6:30PM- 9:30PM

11/14/13– Washington, DC - Free Trial Class- 6:30PM-9:30PM

11/17/13– Santa Monica, CA - Free Trial Class-  5:30PM- 8:30PM

11/17/13-Online - Free Trial Class-  7:00AM- 10:00AM (EDT)

Looking for more free events? Check out our Free Events Listings Page.“

“

We invite you to test your GMAT knowledge for a chance to win! Each week, we will post a new Challenge Problem for you to attempt. If you submit the correct answer, you will be entered into that week’s drawing for a free Manhattan GMAT Prep item. Tell your friends to get out their scrap paper and start solving!

Here is this week’s problem:

How many different pairs of integers (a, b) exist such that 2 < a < 200 and a + b > a^b ?  (Two pairs of numbers are considered different if either a or b differs.  For example, (2, 3) and (2, 4) are considered different, although they don’t satisfy the requirements of this problem.)

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Is that a comparison?

One way to classify conclusions on GMAT Critical Reasoning conclusions is comparative versus absolute.  Why should you care about this classification?  Because this distinction can be very helpful in eliminating wrong answers and finding right answer.

A comparative conclusion will make a comparison between two or more groups.

Car A is better family car than Car B.

An absolute conclusion will just express an opinion about one specific topic or situation.

Therefore, A monorail should not be installed in Town C’s central district.

As a start, let’s get used to classifying conclusions as absolute or comparative.  If the conclusion is comparative, identify the two groups being compared.

1) Therefore, children in the United States who spend at least two hours a day outdoors are less likely to be obese than other children.

2) Thus, Springfield’s recycling program is likely to achieve its aim.

3) For these reasons, isolationism should not be considered a viable trade strategy.

4) The service sector will become more important to Caloda’s economy in the future.

5) Brand D is the best brand of vacuum cleaner available.

(See bottom of this post for answers)

Now that you are comfortable identifying different types of conclusions, we will consider how this classification will help you find the right answer. In many critical reason question types, your job in finding the answer is to influence the conclusion (strengthen the conclusion, weaken the conclusion, find the assumption).  Let’s consider answer choices that are most likely to influence these different types of conclusions. Read more

“Here are the free GMAT events we’re holding this week. All times are local unless otherwise specified.

11/4/13– Evanston, IL – Free Trial Class-  6:30PM- 9:30PM

11/5/13- Denver, CO- Free Trial Class- 6:30PM- 9:30PM

11/5/13– Dallas, TX- Free Trial Class- 6:30PM- 9:30PM

11/5/13–  Atlanta, GA-Free Trial Class- 6:30PM- 9:30PM

11/6/13– New York, NY-Free Trial Class- 7:30PM- 9:00PM

11/6/13– Washington, DC- Free Trial Class- 6:30PM- 9:30PM

11/6/13– Online - Free Trial Class-  8:00PM- 11:00PM (EDT)

11/6/13– San Francisco, CA- Assessing Your MBA Profile presented by mbaMission -  6:00PM- 7:30PM

11/7/13– Washington, DC - Choosing the Right B-School presented by mbaMission-  7:00PM- 8:30PM

11/9/13– Boston, MA- Free Trial Class- 2:00PM- 5:00PM

11/9/13– Santa Clara, CA - Free Trial Class- 2:00PM- 5:00PM

11/9/13– New York, NY - Free Trial Class-  2:00PM- 5:00PM

11/9/13– San Francisco, CA - Free Trial Class-  10:00AM- 1:00PM (EDT)

11/10/13– Houston, TX - Free Trial Class-  6:00PM- 9:00PM (EDT)

11/10/13-Online - Free Trial Class-  2:00PM- 5:00PM (EDT)

Looking for more free events? Check out our Free Events Listings Page.”

“We hope everyone had a happy Halloween! Yesterday we asked our friends on our Manhattan GMAT Facebook page to attempt this spooky Halloween Challenge Problem. As promised, today we are sharing the answer and explanation to the problem:

This question is not as complicated as it may initially seem. The trick is to recognize a recurring pattern in the assignment of the ghouls.

First, we have five ghouls (let’s call them a, b, c, d, and e) and we have to break them down into pairs. So how many pairs are possible in a group of five distinct entities?

We could use the combinations formula: ,

where n is the number of items you are selecting from (the pool) and k is the number of items you are selecting (the subgroup).

Here we would get .

So there are 10 different pairs in a group of 5 individuals.

However, in this particular case, it is actually more helpful to write them out (since there are only 5 ghouls and 10 pairs, it is not so onerous): ab, ac, ad, ae, bc, bd, be, cd, ce, de. Now, on the first night (Monday), any one of the ten pairs may be assigned, since no one has worked yet. Let’s say that pair ab is assigned to work the first night. That means no pair containing either a or b may be assigned on Tuesday night. That rules out 7 of the 10 pairs, leaving only cd, ce, and de available for assignment. If, say, cd were assigned on Tuesday, then on Wednesday no pair containing either c or d could be assigned. This leaves only 3 pairs available for Wednesday: ab, ae, and be.

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